7/(2x5^3)+3/(4x5^2)

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Solution for 7/(2x5^3)+3/(4x5^2) equation: 


D( x )

4*x^(5^2) = 0

2*x^(5^3) = 0

4*x^(5^2) = 0

4*x^(5^2) = 0

4*x^25 = 0 // : 4

x^25 = 0

x = 0

2*x^(5^3) = 0

2*x^(5^3) = 0

2*x^125 = 0 // : 2

x^125 = 0

x = 0

x in (-oo:0) U (0:+oo)

3/(4*x^(5^2))+7/(2*x^(5^3)) = 0

3/4*x^-25+7/2*x^-125 = 0

t_1 = x^-25

7/2*t_1^5+3/4*t_1^1 = 0

7/2*t_1^5+3/4*t_1 = 0

1/2*t_1*(7*t_1^4+3/2) = 0

7*t_1^4 = -3/2 // : 7

t_1^4 = -3/14

t_1/2 = 0

1/2*t_1 = 0 // : 1/2

t_1 = 0

t_1 = 0

x^-25+0 = 0

x^-25 = 0

1*x^-25 = 0 // : 1

x^-25 = 0

x naleu017Cy do O

x belongs to the empty set

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